useNumericLiterals
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Summary
Section titled “Summary”- Rule available since:
v1.0.0 - Diagnostic Category:
lint/complexity/useNumericLiterals - This rule is recommended, which means is enabled by default.
- This rule has a safe fix.
- The default severity of this rule is warning.
- Sources:
- Same as
prefer-numeric-literals
- Same as
Description
Section titled “Description”Disallow parseInt() and Number.parseInt() in favor of binary, octal, and hexadecimal literals
JavaScript provides literal forms for binary, octal, and hexadecimal numbers.
For example: 0b11, 0o77, and 0xff.
Using the literal forms enable static code analysis and avoid unnecessary computations.
Examples
Section titled “Examples”Invalid
Section titled “Invalid”parseInt("111110111", 2);code-block.js:1:1 lint/complexity/useNumericLiterals FIXABLE ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
⚠ This call to parseInt() can be replaced by a binary literal.
> 1 │ parseInt(“111110111”, 2);
│ ^^^^^^^^^^^^^^^^^^^^^^^^
2 │
ℹ Using a literal avoids unnecessary computations.
ℹ Safe fix: Use the computed binary literal instead.
1 │ - parseInt(“111110111”,·2);
1 │ + 0b111110111;
2 2 │
Number.parseInt("767", 8);code-block.js:1:1 lint/complexity/useNumericLiterals FIXABLE ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
⚠ This call to Number.parseInt() can be replaced by an octal literal.
> 1 │ Number.parseInt(“767”, 8);
│ ^^^^^^^^^^^^^^^^^^^^^^^^^
2 │
ℹ Using a literal avoids unnecessary computations.
ℹ Safe fix: Use the computed octal literal instead.
1 │ - Number.parseInt(“767”,·8);
1 │ + 0o767;
2 2 │
Number.parseInt("-1f7", 16);code-block.js:1:1 lint/complexity/useNumericLiterals FIXABLE ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━
⚠ This call to Number.parseInt() can be replaced by a hexadecimal literal.
> 1 │ Number.parseInt(“-1f7”, 16);
│ ^^^^^^^^^^^^^^^^^^^^^^^^^^^
2 │
ℹ Using a literal avoids unnecessary computations.
ℹ Safe fix: Use the computed hexadecimal literal instead.
1 │ - Number.parseInt(“-1f7”,·16);
1 │ + -0x1f7;
2 2 │
parseInt(1);parseInt(1, 3);Number.parseInt(1);Number.parseInt(1, 3);
0b111110111 === 503;0o767 === 503;0x1F7 === 503;
a[parseInt](1,2);
parseInt(foo);parseInt(foo, 2);Number.parseInt(foo);Number.parseInt(foo, 2);How to configure
Section titled “How to configure”{ "linter": { "rules": { "complexity": { "useNumericLiterals": "error" } } }}