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noUnusedTemplateLiteral

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Diagnostic Category: lint/style/noUnusedTemplateLiteral

Since: v1.0.0

Disallow template literals if interpolation and special-character handling are not needed

Examples

Section titled Examples

Invalid

Section titled Invalid
const foo = `bar`
code-block.js:1:13 lint/style/noUnusedTemplateLiteral  FIXABLE  ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

  ✖ Do not use template literals if interpolation and special-character handling are not needed.
  
  > 1 │ const foo = bar
      │             ^^^^^
    2 │ 
  
  ℹ Unsafe fix: Replace with string literal
  
    1   │ - const·foo·=·</strong></span><span style="color: Tomato;">b</span><span style="color: Tomato;">a</span><span style="color: Tomato;">r</span><span style="color: Tomato;"><strong>
      1 │ + const·foo·=·“bar”
    2 2 │   
  
const foo = `bar `
code-block.js:1:13 lint/style/noUnusedTemplateLiteral  FIXABLE  ━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━━

  ✖ Do not use template literals if interpolation and special-character handling are not needed.
  
  > 1 │ const foo = bar 
      │             ^^^^^^
    2 │ 
  
  ℹ Unsafe fix: Replace with string literal
  
    1   │ - const·foo·=·</strong></span><span style="color: Tomato;">b</span><span style="color: Tomato;">a</span><span style="color: Tomato;">r</span><span style="color: Tomato;"><span style="opacity: 0.8;">·</span></span><span style="color: Tomato;"><strong>
      1 │ + const·foo·=·“bar·”
    2 2 │

Valid

Section titled Valid
const foo = `bar
has newline`;
const foo = `"bar"`
const foo = `'bar'`
Section titled Related links